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Capacitor in Parallel

Posted on : Sun , 01 2014 by : virusi

Theory of operation :

Capacitors that are connected in parallel can be considered as a bigger capacitor because capacitance of all capacitors that are connected in parallel are summed.
So adding capacitor in parallel will increase the space available to store charge and will therefore increase the total capacitance.
\large Q_{Total} = Q_{1}+Q_{2}+Q_{3}+...+Q_{n}
Using capacitance equation (Q = C*V) we can overwrite the (1) equation :
\large V*C_{T} = V*C_{1}+V*C_{2}+V*C_{3}+...+V*C_{n}
We can remove Voltage form the (2) equation because voltage across all capacitors are the same :
\large C_{T} = C_{1} + C_{2} + C_{3} + ... + C_{n}
As you can see capacitance is similar to resistance in series so the same tips and tricks from resistors in series can be used

Practical Example :

If you don’t see the example below than you should follow this steps:

– In your browser allow Java SE 7.

– Lower you java security settings (Go to Control Panel >> Java >> Security and set the security level to medium) .

– Edit Site List (Go to Control Panel >> Java >> Security and click on Edit Site List… and add in the list).

Sorry, you need a Java-enabled browser to see the simulation. This is a very simple circuit with 4 resistors, 3 capacitors and 2 switches. If you want to charge the capacitors than the 1 switch should be closed and the 2 switch should be opened. If you want to discharge the capacitors than you should close the 2 switch and open the 1 switch. The charge/discharge time depends on the resistance value of the R1-R4 resistors, so if you want your capacitors to charge/discharge faster than you should put a smaller resistance or vice versa if you want your capacitors to charger/discharge slower. The diagrams are showing the current and voltage that are flowing through the capacitor. If you want to change the value of a component just double click on it and insert the desired value.
Last updated on Sat , 08 2014

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